What is (x-8)^2+(y-15)^2=12 ?

The solution to (x-8)^2+(y-15)^2=12 is Circle with (a,b)=(8,15),r=sqrt(12)

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(x-8)^2+(y-15)^2=12

(x - 8)^{2} + (y - 15)^{2} = 12

(a, b) = (8, 15), r = 12

Solution steps

(x - 8)^{2} + (y - 15)^{2} = 12

Rewrite

(x - 8)^{2} + (y - 15)^{2} = 12

in the form of the standard circle equation

(x - 8)^{2} + (y - 15)^{2} = (12)^{2}

Therefore the circle properties are:

(a, b) = (8, 15), r = 12

x^{2} + y^{2} - 10 x - 14 y + 38 = 0

x^{2} + y^{2} - 10 x - 6 y - 2 = 0

(x - 2)^{2} + (y + 9)^{2} = 5

(4 x^{2}) + (4 y^{2}) - 4 x + 2 y + 1 = 0

3 x^{2} + 3 y^{2} + 30 x - 6 y + 75 = 0

What is (x-8)^2+(y-15)^2=12 ?
The solution to (x-8)^2+(y-15)^2=12 is Circle with (a,b)=(8,15),r=sqrt(12)