What is (x-2)^2+(y+9)^2=5 ?

The solution to (x-2)^2+(y+9)^2=5 is Circle with (a,b)=(2,-9),r=sqrt(5)

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(x-2)^2+(y+9)^2=5

(x - 2)^{2} + (y + 9)^{2} = 5

(a, b) = (2, - 9), r = 5

Solution steps

(x - 2)^{2} + (y + 9)^{2} = 5

Rewrite

(x - 2)^{2} + (y + 9)^{2} = 5

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 9))^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (2, - 9), r = 5

(4 x^{2}) + (4 y^{2}) - 4 x + 2 y + 1 = 0

3 x^{2} + 3 y^{2} + 30 x - 6 y + 75 = 0

x^{2} + y^{2} - 3.6 x + 4.8 y = 11.25

x^{2} + y^{2} + \frac{1}{2} x + y - \frac{5}{4} = 0

(x + 4)^{2} + (y - 5)^{2} = 16

What is (x-2)^2+(y+9)^2=5 ?
The solution to (x-2)^2+(y+9)^2=5 is Circle with (a,b)=(2,-9),r=sqrt(5)