What is x^2+y^2-10x-14y+38=0 ?

The solution to x^2+y^2-10x-14y+38=0 is Circle with (a,b)=(5,7),r=6

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x^2+y^2-10x-14y+38=0

x^{2} + y^{2} - 10 x - 14 y + 38 = 0

(a, b) = (5, 7), r = 6

Solution steps

x^{2} + y^{2} - 10 x - 14 y + 38 = 0

Rewrite

x^{2} + y^{2} - 10 x - 14 y + 38 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - 7)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (5, 7), r = 6

x^{2} + y^{2} - 10 x - 6 y - 2 = 0

(x - 2)^{2} + (y + 9)^{2} = 5

(4 x^{2}) + (4 y^{2}) - 4 x + 2 y + 1 = 0

3 x^{2} + 3 y^{2} + 30 x - 6 y + 75 = 0

x^{2} + y^{2} - 3.6 x + 4.8 y = 11.25

What is x^2+y^2-10x-14y+38=0 ?
The solution to x^2+y^2-10x-14y+38=0 is Circle with (a,b)=(5,7),r=6