What is the domain of sqrt((-x^2+16)(x+3)) ?

The domain of sqrt((-x^2+16)(x+3)) is x<=-4\lor-3<= x<= 4

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domain of sqrt((-x^2+16)(x+3))

domain

(- x^{2} + 16) (x + 3)

x \leq - 4 or - 3 \leq x \leq 4

Interval Notation

(- \infty, - 4] \cup [- 3, 4]

Solution steps

Find non-negative values for radicals:

x \leq - 4 or - 3 \leq x \leq 4

The function domain

x \leq - 4 or - 3 \leq x \leq 4

f (x) = \frac{3 x ^{2}}{x ^{2} - 9}

y = \frac{3 x - 1}{2 x + 8}

f (x) = - 5

f (x) = \frac{1}{x + 4 - 2}

(x - 6)^{2}

What is the domain of sqrt((-x^2+16)(x+3)) ?
The domain of sqrt((-x^2+16)(x+3)) is x<=-4\lor-3<= x<= 4