What is the domain of (sqrt(x-6))^2 ?

The domain of (sqrt(x-6))^2 is x>= 6

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domain of (sqrt(x-6))^2

domain

(x - 6)^{2}

x \geq 6

Interval Notation

[6, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 6

The function domain

x \geq 6

\frac{x - 2}{2 x - 4}

f (x) = \frac{( x - 2 )}{( x + 2 )}

f (x) = \frac{x - 4}{x ^{2} - 12 x + 32}

y = - \frac{5}{4} x - 2, (10, - 10)

csc (csc (x))