What is the domain of f(x)= 1/(sqrt(x+4)-2) ?

The domain of f(x)= 1/(sqrt(x+4)-2) is -4 0

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domain of f(x)= 1/(sqrt(x+4)-2)

domain

f (x) = \frac{1}{x + 4 - 2}

- 4 \leq x < 0 or x > 0

Interval Notation

[- 4, 0) \cup (0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 4

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 4 \leq x < 0 or x > 0

(x - 6)^{2}

\frac{x - 2}{2 x - 4}

f (x) = \frac{( x - 2 )}{( x + 2 )}

f (x) = \frac{x - 4}{x ^{2} - 12 x + 32}

y = - \frac{5}{4} x - 2, (10, - 10)

What is the domain of f(x)= 1/(sqrt(x+4)-2) ?
The domain of f(x)= 1/(sqrt(x+4)-2) is -4<= x<0\lor x>0