What are the solutions to the equation X^2+2X-8=0 ?

The solutions to the equation X^2+2X-8=0 are X=2,X=-4

Find the zeros of X^2+2X-8=0

The zeros of X^2+2X-8=0 are X=2,X=-4

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X^{2} + 2 X - 8 = 0

X = 2, X = - 4

Solution steps

X^{2} + 2 X - 8 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 8) = 6

X_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 2 + 6}{2 \cdot 1}, X_{2} = \frac{- 2 - 6}{2 \cdot 1}

X = \frac{- 2 + 6}{2 \cdot 1} : 2

X = \frac{- 2 - 6}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

X = 2, X = - 4

4 x^{3} - 12 x^{2} > 0

- 3 y^{2} - 6 y + 2 = 0

3 (u + 2) + u = 4 (u - 1) + 10

h^{2} + 6 h - 5 = 0

- 9 x + 2 > 18 and 13 x + 15 \leq - 4

What are the solutions to the equation X^2+2X-8=0 ?
The solutions to the equation X^2+2X-8=0 are X=2,X=-4
Find the zeros of X^2+2X-8=0
The zeros of X^2+2X-8=0 are X=2,X=-4