What is the answer to 3(u+2)+u=4(u-1)+10 ?

The answer to 3(u+2)+u=4(u-1)+10 is True for all u

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3(u+2)+u=4(u-1)+10

3 (u + 2) + u = 4 (u - 1) + 10

True for all u

Solution steps

3 (u + 2) + u = 4 (u - 1) + 10

Expand

3 (u + 2) + u : 4 u + 6

Expand

4 (u - 1) + 10 : 4 u + 6

4 u + 6 = 4 u + 6

Move

6

to the right side

4 u = 4 u

Move

4 u

to the left side

0 = 0

Both sides are equal

True for all u

h^{2} + 6 h - 5 = 0

- 9 x + 2 > 18 and 13 x + 15 \leq - 4

0 = x^{2} + 16 x - 5

2 x + 7 = - 11

x^{2} - 27 = 6 x

What is the answer to 3(u+2)+u=4(u-1)+10 ?
The answer to 3(u+2)+u=4(u-1)+10 is True for all u
Solve for u: 3(u+2)+u=4(u-1)+10
The solution is True for all u