What are the solutions to the equation h^2+6h-5=0 ?

The solutions to the equation h^2+6h-5=0 are h=-3+sqrt(14),h=-3-sqrt(14)

Find the zeros of h^2+6h-5=0

The zeros of h^2+6h-5=0 are h=-3+sqrt(14),h=-3-sqrt(14)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

h^{2} + 6 h - 5 = 0

h = - 3 + 14, h = - 3 - 14

Decimal Notation

h = 0.74165 \dots, h = - 6.74165 \dots

Solution steps

h^{2} + 6 h - 5 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 5) = 214

h_{1, 2} = \frac{- 6 \pm 2 14}{2 \cdot 1}

Separate the solutions

h_{1} = \frac{- 6 + 2 14}{2 \cdot 1}, h_{2} = \frac{- 6 - 2 14}{2 \cdot 1}

h = \frac{- 6 + 2 14}{2 \cdot 1} : - 3 + 14

h = \frac{- 6 - 2 14}{2 \cdot 1} : - 3 - 14

The solutions to the quadratic equation are:

h = - 3 + 14, h = - 3 - 14

- 9 x + 2 > 18 and 13 x + 15 \leq - 4

0 = x^{2} + 16 x - 5

2 x + 7 = - 11

x^{2} - 27 = 6 x

16 x = 6 x + 100

What are the solutions to the equation h^2+6h-5=0 ?
The solutions to the equation h^2+6h-5=0 are h=-3+sqrt(14),h=-3-sqrt(14)
Find the zeros of h^2+6h-5=0
The zeros of h^2+6h-5=0 are h=-3+sqrt(14),h=-3-sqrt(14)