What is the general solution for 2sqrt(3)*sin(4x+60^0)-3=0 ?

The general solution for 2sqrt(3)*sin(4x+60^0)-3=0 is x=-1/4+pi/(12)+(pin)/2 ,x=-1/4+pi/6+(pin)/2

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2sqrt(3)*sin(4x+60^0)-3=0

Solution

23 \cdot sin (4 x + 6 0^{0}) - 3 = 0

Solution

x = - \frac{1}{4} + \frac{π}{12} + \frac{πn}{2}, x = - \frac{1}{4} + \frac{π}{6} + \frac{πn}{2}

Degrees

x = 0.67605 \dots^{\circ} + 9 0^{\circ} n, x = 15.67605 \dots^{\circ} + 9 0^{\circ} n

Solution steps

23 sin (4 x + 6 0^{0}) - 3 = 0

Move

3

to the right side

23 sin (4 x + 6 0^{0}) - 3 = 0

Add

3

to both sides

23 sin (4 x + 6 0^{0}) - 3 + 3 = 0 + 3

Simplify

23 sin (4 x + 6 0^{0}) = 3

23 sin (4 x + 6 0^{0}) = 3

Divide both sides by

23

23 sin (4 x + 6 0^{0}) = 3

Divide both sides by

23

\frac{2 3 sin ( 4 x + 6 0 ^{0} )}{2 3} = \frac{3}{2 3}

Simplify

\frac{2 3 sin ( 4 x + 6 0 ^{0} )}{2 3} = \frac{3}{2 3}

Simplify

\frac{2 3 sin ( 4 x + 6 0 ^{0} )}{2 3} : sin (4 x + 6 0^{0})

\frac{2 3 sin ( 4 x + 6 0 ^{0} )}{2 3}

Divide the numbers:

\frac{2}{2} = 1

= \frac{3 sin ( 4 x + 6 0 ^{0} )}{3}

Cancel the common factor:

3

= sin (4 x + 6 0^{0})

Simplify

\frac{3}{2 3} : \frac{3}{2}

\frac{3}{2 3}

Apply radical rule:

3 = 3^{\frac{1}{2}}

= \frac{3}{2 \cdot 3 ^{\frac{1}{2}}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{3 ^{1}}{3 ^{\frac{1}{2}}} = 3^{1 - \frac{1}{2}}

= \frac{3 ^{1 - \frac{1}{2}}}{2}

Subtract the numbers:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{3 ^{\frac{1}{2}}}{2}

Apply radical rule:

3^{\frac{1}{2}} = 3

= \frac{3}{2}

sin (4 x + 6 0^{0}) = \frac{3}{2}

sin (4 x + 6 0^{0}) = \frac{3}{2}

sin (4 x + 6 0^{0}) = \frac{3}{2}

General solutions for

sin (4 x + 6 0^{0}) = \frac{3}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

4 x + 6 0^{0} = \frac{π}{3} + 2 πn, 4 x + 6 0^{0} = \frac{2 π}{3} + 2 πn

4 x + 6 0^{0} = \frac{π}{3} + 2 πn, 4 x + 6 0^{0} = \frac{2 π}{3} + 2 πn

Solve

4 x + 6 0^{0} = \frac{π}{3} + 2 πn : x = - \frac{1}{4} + \frac{π}{12} + \frac{πn}{2}

4 x + 6 0^{0} = \frac{π}{3} + 2 πn

Apply rule

a^{0} = 1, a \neq = 0

6 0^{0} = 1

4 x + 1 = \frac{π}{3} + 2 πn

Move

1

to the right side

4 x + 1 = \frac{π}{3} + 2 πn

Subtract

1

from both sides

4 x + 1 - 1 = \frac{π}{3} + 2 πn - 1

Simplify

4 x = \frac{π}{3} + 2 πn - 1

4 x = \frac{π}{3} + 2 πn - 1

Divide both sides by

4

4 x = \frac{π}{3} + 2 πn - 1

Divide both sides by

4

\frac{4 x}{4} = \frac{\frac{π}{3}}{4} + \frac{2 πn}{4} - \frac{1}{4}

Simplify

\frac{4 x}{4} = \frac{\frac{π}{3}}{4} + \frac{2 πn}{4} - \frac{1}{4}

Simplify

\frac{4 x}{4} : x

\frac{4 x}{4}

Divide the numbers:

\frac{4}{4} = 1

= x

Simplify

\frac{\frac{π}{3}}{4} + \frac{2 πn}{4} - \frac{1}{4} : - \frac{1}{4} + \frac{π}{12} + \frac{πn}{2}

\frac{\frac{π}{3}}{4} + \frac{2 πn}{4} - \frac{1}{4}

Group like terms

= - \frac{1}{4} + \frac{2 πn}{4} + \frac{\frac{π}{3}}{4}

\frac{2 πn}{4} = \frac{πn}{2}

\frac{2 πn}{4}

Cancel the common factor:

2

= \frac{πn}{2}

\frac{\frac{π}{3}}{4} = \frac{π}{12}

\frac{\frac{π}{3}}{4}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{3 \cdot 4}

Multiply the numbers:

3 \cdot 4 = 12

= \frac{π}{12}

= - \frac{1}{4} + \frac{πn}{2} + \frac{π}{12}

Group like terms

= - \frac{1}{4} + \frac{π}{12} + \frac{πn}{2}

x = - \frac{1}{4} + \frac{π}{12} + \frac{πn}{2}

x = - \frac{1}{4} + \frac{π}{12} + \frac{πn}{2}

x = - \frac{1}{4} + \frac{π}{12} + \frac{πn}{2}

Solve

4 x + 6 0^{0} = \frac{2 π}{3} + 2 πn : x = - \frac{1}{4} + \frac{π}{6} + \frac{πn}{2}

4 x + 6 0^{0} = \frac{2 π}{3} + 2 πn

Apply rule

a^{0} = 1, a \neq = 0

6 0^{0} = 1

4 x + 1 = \frac{2 π}{3} + 2 πn

Move

1

to the right side

4 x + 1 = \frac{2 π}{3} + 2 πn

Subtract

1

from both sides

4 x + 1 - 1 = \frac{2 π}{3} + 2 πn - 1

Simplify

4 x = \frac{2 π}{3} + 2 πn - 1

4 x = \frac{2 π}{3} + 2 πn - 1

Divide both sides by

4

4 x = \frac{2 π}{3} + 2 πn - 1

Divide both sides by

4

\frac{4 x}{4} = \frac{\frac{2 π}{3}}{4} + \frac{2 πn}{4} - \frac{1}{4}

Simplify

\frac{4 x}{4} = \frac{\frac{2 π}{3}}{4} + \frac{2 πn}{4} - \frac{1}{4}

Simplify

\frac{4 x}{4} : x

\frac{4 x}{4}

Divide the numbers:

\frac{4}{4} = 1

= x

Simplify

\frac{\frac{2 π}{3}}{4} + \frac{2 πn}{4} - \frac{1}{4} : - \frac{1}{4} + \frac{π}{6} + \frac{πn}{2}

\frac{\frac{2 π}{3}}{4} + \frac{2 πn}{4} - \frac{1}{4}

Group like terms

= - \frac{1}{4} + \frac{2 πn}{4} + \frac{\frac{2 π}{3}}{4}

\frac{2 πn}{4} = \frac{πn}{2}

\frac{2 πn}{4}

Cancel the common factor:

2

= \frac{πn}{2}

\frac{\frac{2 π}{3}}{4} = \frac{π}{6}

\frac{\frac{2 π}{3}}{4}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{2 π}{3 \cdot 4}

Multiply the numbers:

3 \cdot 4 = 12

= \frac{2 π}{12}

Cancel the common factor:

2

= \frac{π}{6}

= - \frac{1}{4} + \frac{πn}{2} + \frac{π}{6}

Group like terms

= - \frac{1}{4} + \frac{π}{6} + \frac{πn}{2}

x = - \frac{1}{4} + \frac{π}{6} + \frac{πn}{2}

x = - \frac{1}{4} + \frac{π}{6} + \frac{πn}{2}

x = - \frac{1}{4} + \frac{π}{6} + \frac{πn}{2}

x = - \frac{1}{4} + \frac{π}{12} + \frac{πn}{2}, x = - \frac{1}{4} + \frac{π}{6} + \frac{πn}{2}

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Frequently Asked Questions (FAQ)

What is the general solution for 2sqrt(3)*sin(4x+60^0)-3=0 ?
The general solution for 2sqrt(3)*sin(4x+60^0)-3=0 is x=-1/4+pi/(12)+(pin)/2 ,x=-1/4+pi/6+(pin)/2