What is the general solution for cos^2(x)+sin^2(x)+sin(x)= 1/2 ?

The general solution for cos^2(x)+sin^2(x)+sin(x)= 1/2 is x=(7pi)/6+2pin,x=(11pi)/6+2pin

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cos^2(x)+sin^2(x)+sin(x)= 1/2

cos^{2} (x) + sin^{2} (x) + sin (x) = \frac{1}{2}

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Degrees

x = 21 0^{\circ} + 36 0^{\circ} n, x = 33 0^{\circ} + 36 0^{\circ} n

Solution steps

cos^{2} (x) + sin^{2} (x) + sin (x) = \frac{1}{2}

Rewrite using trig identities

cos^{2} (x) + sin^{2} (x) + sin (x)

Use the Pythagorean identity:

cos^{2} (x) + sin^{2} (x) = 1

= sin (x) + 1

sin (x) + 1 = \frac{1}{2}

Move

1

to the right side

sin (x) + 1 = \frac{1}{2}

Subtract

1

from both sides

sin (x) + 1 - 1 = \frac{1}{2} - 1

Simplify

sin (x) + 1 - 1 = \frac{1}{2} - 1

Simplify

sin (x) + 1 - 1 : sin (x)

sin (x) + 1 - 1

Add similar elements:

1 - 1 = 0

= sin (x)

Simplify

\frac{1}{2} - 1 : - \frac{1}{2}

\frac{1}{2} - 1

Convert element to fraction:

1 = \frac{1 \cdot 2}{2}

= - \frac{1 \cdot 2}{2} + \frac{1}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 \cdot 2 + 1}{2}

- 1 \cdot 2 + 1 = - 1

- 1 \cdot 2 + 1

Multiply the numbers:

1 \cdot 2 = 2

= - 2 + 1

Add/Subtract the numbers:

- 2 + 1 = - 1

= - 1

= \frac{- 1}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{1}{2}

sin (x) = - \frac{1}{2}

sin (x) = - \frac{1}{2}

sin (x) = - \frac{1}{2}

General solutions for

sin (x) = - \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

2 sin (x) cos^{2} (x) - 1 + 2 cos^{2} (x) - sin (x) = 0

tan^{2} (b) = 3

a, sin (a + \frac{b}{2}) = cos (\frac{c}{2})

tan (x) - cot (x) = 2 cot^{2} (x)

cot (\frac{- x + 3 n}{4}) = 0

What is the general solution for cos^2(x)+sin^2(x)+sin(x)= 1/2 ?
The general solution for cos^2(x)+sin^2(x)+sin(x)= 1/2 is x=(7pi)/6+2pin,x=(11pi)/6+2pin