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(1-sin(x))*cos^3(x)=0

Solução

(1 - sin (x)) \cdot cos^{3} (x) = 0

Solução

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

+1

Graus

x = 9 0^{\circ} + 36 0^{\circ} n, x = 27 0^{\circ} + 36 0^{\circ} n

Passos da solução

(1 - sin (x)) cos^{3} (x) = 0

Resolver cada parte separadamente

1 - sin (x) = 0 or cos^{3} (x) = 0

1 - sin (x) = 0 : x = \frac{π}{2} + 2 πn

1 - sin (x) = 0

Mova

1

para o lado direito

1 - sin (x) = 0

Subtrair

1

de ambos os lados

1 - sin (x) - 1 = 0 - 1

Simplificar

- sin (x) = - 1

- sin (x) = - 1

Dividir ambos os lados por

- 1

- sin (x) = - 1

Dividir ambos os lados por

- 1

\frac{- sin ( x )}{- 1} = \frac{- 1}{- 1}

Simplificar

sin (x) = 1

sin (x) = 1

Soluções gerais para

sin (x) = 1

sin (x)

tabela de periodicidade com ciclo de

2 πn

:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{2} + 2 πn

x = \frac{π}{2} + 2 πn

cos^{3} (x) = 0 : x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

cos^{3} (x) = 0

Aplicar a regra

x^{n} = 0 \Rightarrow x = 0

cos (x) = 0

Soluções gerais para

cos (x) = 0

cos (x)

tabela de periodicidade com ciclo de

2 πn

:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Combinar toda as soluções

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

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3cos^2(x)-sin(x)+1=0

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2sin(x)cos^2(x)-1+2cos^2(x)-sin(x)=0

2 sin (x) cos^{2} (x) - 1 + 2 cos^{2} (x) - sin (x) = 0

tan^{2} (b) = 3