What is the general solution for -3+cos(2x)*2=0 ?

The general solution for -3+cos(2x)*2=0 is No Solution for x\in\mathbb{R}

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-3+cos(2x)*2=0

- 3 + cos (2 x) \cdot 2 = 0

No Solution for x \in R

Solution steps

- 3 + cos (2 x) \cdot 2 = 0

Move

3

to the right side

- 3 + cos (2 x) \cdot 2 = 0

Add

3

to both sides

- 3 + cos (2 x) \cdot 2 + 3 = 0 + 3

Simplify

cos (2 x) \cdot 2 = 3

cos (2 x) \cdot 2 = 3

Divide both sides by

2

cos (2 x) \cdot 2 = 3

Divide both sides by

2

\frac{cos ( 2 x ) \cdot 2}{2} = \frac{3}{2}

Simplify

cos (2 x) = \frac{3}{2}

cos (2 x) = \frac{3}{2}

- 1 \leq cos (x) \leq 1

No Solution for x \in R

\frac{1}{9} + cos^{2} (x) = 1

sin (x) = 0.9063

11 = 12 + 3.5 sin (\frac{2 π}{365} t)

sin (2 t) = 2 sin (t)

cos (α) = 0

What is the general solution for -3+cos(2x)*2=0 ?
The general solution for -3+cos(2x)*2=0 is No Solution for x\in\mathbb{R}