What is the general solution for cos(α)=0 ?

The general solution for cos(α)=0 is α= pi/2+2pin,α=(3pi)/2+2pin

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cos(α)=0

cos (α) = 0

α = \frac{π}{2} + 2 πn, α = \frac{3 π}{2} + 2 πn

Degrees

α = 9 0^{\circ} + 36 0^{\circ} n, α = 27 0^{\circ} + 36 0^{\circ} n

Solution steps

cos (α) = 0

General solutions for

cos (α) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

α = \frac{π}{2} + 2 πn, α = \frac{3 π}{2} + 2 πn

α = \frac{π}{2} + 2 πn, α = \frac{3 π}{2} + 2 πn

x, cos (x^{3} y^{3}) = 5 y^{3}

cos^{2} (\frac{3}{4} π + x) + sin^{2} (\frac{7}{4} π - x) = 1

sin (4 x) = - sin (x)

2 (2) cos (x - 4) sin (x) cos (x) = 0

cos (x) (tan (x) - 3) = 0

What is the general solution for cos(α)=0 ?
The general solution for cos(α)=0 is α= pi/2+2pin,α=(3pi)/2+2pin