What is the general solution for cos(t)=0.5 ?

The general solution for cos(t)=0.5 is t= pi/3+2pin,t=(5pi)/3+2pin

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cos(t)=0.5

cos (t) = 0.5

t = \frac{π}{3} + 2 πn, t = \frac{5 π}{3} + 2 πn

Degrees

t = 6 0^{\circ} + 36 0^{\circ} n, t = 30 0^{\circ} + 36 0^{\circ} n

Solution steps

cos (t) = 0.5

General solutions for

cos (t) = 0.5

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

t = \frac{π}{3} + 2 πn, t = \frac{5 π}{3} + 2 πn

t = \frac{π}{3} + 2 πn, t = \frac{5 π}{3} + 2 πn

cos (2 θ) (4 sin^{2} (θ) + 1) = 0

sin (x) = 0.9906

sin (θ) = - 0.17

2 sin^{2} (x) - 1 = 0, - π \leq x \leq π

sin (θ) = - 0.22

What is the general solution for cos(t)=0.5 ?
The general solution for cos(t)=0.5 is t= pi/3+2pin,t=(5pi)/3+2pin