What is the general solution for sin(θ)=-0.22 ?

The general solution for sin(θ)=-0.22 is θ=-0.22181…+2pin,θ=pi+0.22181…+2pin

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sin(θ)=-0.22

sin (θ) = - 0.22

θ = - 0.22181 \dots + 2 πn, θ = π + 0.22181 \dots + 2 πn

Degrees

θ = - 12.70903 \dots^{\circ} + 36 0^{\circ} n, θ = 192.70903 \dots^{\circ} + 36 0^{\circ} n

Solution steps

sin (θ) = - 0.22

Apply trig inverse properties

sin (θ) = - 0.22

General solutions for

sin (θ) = - 0.22

sin (x) = - a \Rightarrow x = arcsin (- a) + 2 πn, x = π + arcsin (a) + 2 πn

θ = arcsin (- 0.22) + 2 πn, θ = π + arcsin (0.22) + 2 πn

θ = arcsin (- 0.22) + 2 πn, θ = π + arcsin (0.22) + 2 πn

Show solutions in decimal form

θ = - 0.22181 \dots + 2 πn, θ = π + 0.22181 \dots + 2 πn

\frac{3}{2} sec (θ) + 3 cos (θ) = 3

2 sec (x) cos^{2} (x) = csc^{2} (x) - cot^{2} (x)

1 = 7 cos (\frac{π}{3} t)

12 cos^{2} (x) + 2 cos (x) - 2 = 0

sin (θ) = - 0.94

What is the general solution for sin(θ)=-0.22 ?
The general solution for sin(θ)=-0.22 is θ=-0.22181…+2pin,θ=pi+0.22181…+2pin