What is the general solution for cos(2pix)*2pi+2pi=0 ?

The general solution for cos(2pix)*2pi+2pi=0 is x= 1/2+n

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(2pix)*2pi+2pi=0

Solution

cos (2 π x) \cdot 2 π + 2 π = 0

Solution

x = \frac{1}{2} + n

Degrees

x = 28.64788 \dots^{\circ}

Solution steps

cos (2 π x) \cdot 2 π + 2 π = 0

Move

2 π

to the right side

cos (2 π x) \cdot 2 π + 2 π = 0

Subtract

2 π

from both sides

cos (2 π x) \cdot 2 π + 2 π - 2 π = 0 - 2 π

Simplify

cos (2 π x) \cdot 2 π = - 2 π

cos (2 π x) \cdot 2 π = - 2 π

Divide both sides by

2 π

cos (2 π x) \cdot 2 π = - 2 π

Divide both sides by

2 π

\frac{cos ( 2 π x ) \cdot 2 π}{2 π} = \frac{- 2 π}{2 π}

Simplify

cos (2 π x) = - 1

cos (2 π x) = - 1

General solutions for

cos (2 π x) = - 1

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

2 π x = π + 2 πn

2 π x = π + 2 πn

Solve

2 π x = π + 2 πn : x = \frac{1}{2} + n

2 π x = π + 2 πn

Divide both sides by

2 π

2 π x = π + 2 πn

Divide both sides by

2 π

\frac{2 π x}{2 π} = \frac{π}{2 π} + \frac{2 πn}{2 π}

Simplify

\frac{2 π x}{2 π} = \frac{π}{2 π} + \frac{2 πn}{2 π}

Simplify

\frac{2 π x}{2 π} : x

\frac{2 π x}{2 π}

Divide the numbers:

\frac{2}{2} = 1

= \frac{π x}{π}

Cancel the common factor:

π

= x

Simplify

\frac{π}{2 π} + \frac{2 πn}{2 π} : \frac{1}{2} + n

\frac{π}{2 π} + \frac{2 πn}{2 π}

Cancel

\frac{π}{2 π} : \frac{1}{2}

\frac{π}{2 π}

Cancel the common factor:

π

= \frac{1}{2}

= \frac{1}{2} + \frac{2 πn}{2 π}

Cancel

\frac{2 πn}{2 π} : n

\frac{2 πn}{2 π}

Cancel

\frac{2 πn}{2 π} : n

\frac{2 πn}{2 π}

Divide the numbers:

\frac{2}{2} = 1

= \frac{πn}{π}

Cancel the common factor:

π

= n

= n

= \frac{1}{2} + n

x = \frac{1}{2} + n

x = \frac{1}{2} + n

x = \frac{1}{2} + n

x = \frac{1}{2} + n

Popular Examples

solvefor x,sin(y)=ycos(x)solve for

x, sin (y) = y cos (x)

4sin(2x)-sqrt(12)=0,0<= x<= 2pi

4 sin (2 x) - 12 = 0, 0 \leq x \leq 2 π

1*10^6=(400*cos(θ)+700)^2+(400*sin(θ))^2

1 \cdot 1 0^{6} = (400 \cdot cos (θ) + 700)^{2} + (400 \cdot sin (θ))^{2}

sin(x)-0.5*cos(x)=0.768

sin (x) - 0.5 \cdot cos (x) = 0.768

((176)^2)/(300*32.2)=tan(θ+30.9637)

\frac{( 176 ) ^{2}}{300 \cdot 32.2} = tan (θ + 30.963 7^{\circ})

Frequently Asked Questions (FAQ)

What is the general solution for cos(2pix)*2pi+2pi=0 ?
The general solution for cos(2pix)*2pi+2pi=0 is x= 1/2+n