What is the general solution for solvefor t,0=8sin((pit)/(12))+32 ?

The general solution for solvefor t,0=8sin((pit)/(12))+32 is No Solution for t\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor t,0=8sin((pit)/(12))+32

solve for

t, 0 = 8 sin (\frac{π t}{12}) + 32

No Solution for t \in R

Solution steps

0 = 8 sin (\frac{π t}{12}) + 32

Switch sides

8 sin (\frac{π t}{12}) + 32 = 0

Move

32

to the right side

8 sin (\frac{π t}{12}) + 32 = 0

Subtract

32

from both sides

8 sin (\frac{π t}{12}) + 32 - 32 = 0 - 32

Simplify

8 sin (\frac{π t}{12}) = - 32

8 sin (\frac{π t}{12}) = - 32

Divide both sides by

8

8 sin (\frac{π t}{12}) = - 32

Divide both sides by

8

\frac{8 sin ( \frac{π t}{12} )}{8} = \frac{- 32}{8}

Simplify

\frac{8 sin ( \frac{π t}{12} )}{8} = \frac{- 32}{8}

Simplify

\frac{8 sin ( \frac{π t}{12} )}{8} : sin (\frac{π t}{12})

\frac{8 sin ( \frac{π t}{12} )}{8}

Divide the numbers:

\frac{8}{8} = 1

= sin (\frac{π t}{12})

Simplify

\frac{- 32}{8} : - 4

\frac{- 32}{8}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{32}{8}

Divide the numbers:

\frac{32}{8} = 4

= - 4

sin (\frac{π t}{12}) = - 4

sin (\frac{π t}{12}) = - 4

sin (\frac{π t}{12}) = - 4

- 1 \leq sin (x) \leq 1

No Solution for t \in R

sec^{2} (x) = \frac{1}{sin ^{2} ( x )}

2 sin^{2} (x) + sin (x) - 1 = 0, 0 \leq x < 2 π

arctan (x) = \frac{7.8}{- 4.42}

- sin (x + 5^{\circ}) = 0

cos (2 π x) \cdot 2 π + 2 π = 0

What is the general solution for solvefor t,0=8sin((pit)/(12))+32 ?
The general solution for solvefor t,0=8sin((pit)/(12))+32 is No Solution for t\in\mathbb{R}