What is the general solution for 2cot(θ)-1=2,cot(θ)-1=0 ?

The general solution for 2cot(θ)-1=2,cot(θ)-1=0 is No Solution for θ\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2cot(θ)-1=2,cot(θ)-1=0

2 cot (θ) - 1 = 2, cot (θ) - 1 = 0

No Solution for θ \in R

Solution steps

2 cot (θ) - 1 = 2, cot (θ) - 1 = 0

Move

1

to the right side

2 cot (θ) - 1 = 2

Add

1

to both sides

2 cot (θ) - 1 + 1 = 2 + 1

Simplify

2 cot (θ) = 3

2 cot (θ) = 3

Divide both sides by

2

2 cot (θ) = 3

Divide both sides by

2

\frac{2 cot ( θ )}{2} = \frac{3}{2}

Simplify

cot (θ) = \frac{3}{2}

cot (θ) = \frac{3}{2}

Apply trig inverse properties

cot (θ) = \frac{3}{2}

General solutions for

cot (θ) = \frac{3}{2}

cot (x) = a \Rightarrow x = arccot (a) + πn

θ = arccot (\frac{3}{2}) + πn

θ = arccot (\frac{3}{2}) + πn

Solutions for the range

cot (θ) - 1 = 0

No Solution for θ \in R

2 cos^{2} (a) - 7 cos (a) + 3 = 0

y, x = 2 cos (2 y)

- 3 - 6 cos (x) = 0

tan (θ) = \frac{26}{53}

n, y = - sin (2 (\frac{π}{4} + πn)) 2

What is the general solution for 2cot(θ)-1=2,cot(θ)-1=0 ?
The general solution for 2cot(θ)-1=2,cot(θ)-1=0 is No Solution for θ\in\mathbb{R}