What is the general solution for 5sec^2(x)-5=0,0<= x<= 2pi ?

Q: What is the general solution for 5sec^2(x)-5=0,0<= x<= 2pi ?

The general solution for 5sec^2(x)-5=0,0<= x<= 2pi is x=0,x=2pi,x=pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5sec^2(x)-5=0,0<= x<= 2pi

Solution

5 sec^{2} (x) - 5 = 0, 0 \leq x \leq 2 π

Solution

x = 0, x = 2 π, x = π

Degrees

x = 0^{\circ}, x = 36 0^{\circ}, x = 18 0^{\circ}

Solution steps

5 sec^{2} (x) - 5 = 0, 0 \leq x \leq 2 π

Solve by substitution

5 sec^{2} (x) - 5 = 0

Let:

sec (x) = u

5 u^{2} - 5 = 0

5 u^{2} - 5 = 0 : u = 1, u = - 1

5 u^{2} - 5 = 0

Move

5

to the right side

5 u^{2} - 5 = 0

Add

5

to both sides

5 u^{2} - 5 + 5 = 0 + 5

Simplify

5 u^{2} = 5

5 u^{2} = 5

Divide both sides by

5

5 u^{2} = 5

Divide both sides by

5

\frac{5 u ^{2}}{5} = \frac{5}{5}

Simplify

u^{2} = 1

u^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

u = 1, u = - 1

1 = 1

1

Apply rule

1 = 1

= 1

- 1 = - 1

- 1

Apply rule

1 = 1

= - 1

u = 1, u = - 1

Substitute back

u = sec (x)

sec (x) = 1, sec (x) = - 1

sec (x) = 1, sec (x) = - 1

sec (x) = 1, 0 \leq x \leq 2 π : x = 0, x = 2 π

sec (x) = 1, 0 \leq x \leq 2 π

General solutions for

sec (x) = 1

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

x = 0 + 2 πn

x = 0 + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = 0, x = 2 π

sec (x) = - 1, 0 \leq x \leq 2 π : x = π

sec (x) = - 1, 0 \leq x \leq 2 π

General solutions for

sec (x) = - 1

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

x = π + 2 πn

x = π + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = π

Combine all the solutions

x = 0, x = 2 π, x = π

Popular Examples

4cos^2(θ)+4=5

4 cos^{2} (θ) + 4 = 5

4sin(2z)-3cos(z)=0

4 sin (2 z) - 3 cos (z) = 0

0.34=cos(x)

0.34 = cos (x)

7sin(x)cos(x)+cos^2(x)=1

7 sin (x) cos (x) + cos^{2} (x) = 1

(tan(x)-1)(cos(x)-1)=0

(tan (x) - 1) (cos (x) - 1) = 0

Frequently Asked Questions (FAQ)

What is the general solution for 5sec^2(x)-5=0,0<= x<= 2pi ?
The general solution for 5sec^2(x)-5=0,0<= x<= 2pi is x=0,x=2pi,x=pi