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Popular >

40cos(120)

Solution

40 cos (12 0^{\circ})

Solution

- 20

Solution steps

40 cos (12 0^{\circ})

Use the following trivial identity:

cos (12 0^{\circ}) = - \frac{1}{2}

cos (12 0^{\circ})

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= - \frac{1}{2}

= 40 (- \frac{1}{2})

Simplify

40 (- \frac{1}{2}) : - 20

40 (- \frac{1}{2})

Remove parentheses:

(- a) = - a

= - 40 \cdot \frac{1}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{1 \cdot 40}{2}

Multiply the numbers:

1 \cdot 40 = 40

= - \frac{40}{2}

Divide the numbers:

\frac{40}{2} = 20

= - 20

= - 20

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arcsin (\frac{84}{48} sin (3 0^{\circ}))

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0.15(9.8)(cos(32))+0.91(cos(58))

0.15 (9.8) (cos (3 2^{\circ})) + 0.91 (cos (5 8^{\circ}))

Frequently Asked Questions (FAQ)

What is the value of 40cos(120) ?
The value of 40cos(120) is -20