What is the value of cos^2(pi/2)-3sin(pi/2) ?

The value of cos^2(pi/2)-3sin(pi/2) is -3

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cos^2(pi/2)-3sin(pi/2)

cos^{2} (\frac{π}{2}) - 3 sin (\frac{π}{2})

- 3

Solution steps

cos^{2} (\frac{π}{2}) - 3 sin (\frac{π}{2})

Use the following trivial identity:

cos (\frac{π}{2}) = 0

cos (\frac{π}{2})

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 0

Use the following trivial identity:

sin (\frac{π}{2}) = 1

sin (\frac{π}{2})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 1

= 0^{2} - 3 \cdot 1

Simplify

= - 3

0.15 (9.8) (cos (3 2^{\circ})) + 0.91 (cos (5 8^{\circ}))

arcsec (\frac{2}{3})

arctan (\frac{10}{9})

arccos (0.47)

2 (4 (0)^{3} cosh (0^{2}) + 6 (0) sinh (0^{2}))

What is the value of cos^2(pi/2)-3sin(pi/2) ?
The value of cos^2(pi/2)-3sin(pi/2) is -3