What is ((x-2)^2)/(3^2)+((y-1)^2)/(2^2)=1 ?

The solution to ((x-2)^2)/(3^2)+((y-1)^2)/(2^2)=1 is Ellipse with (h,k)=(2,1),a=3,b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-2)^2)/(3^2)+((y-1)^2)/(2^2)=1

\frac{( x - 2 ) ^{2}}{3 ^{2}} + \frac{( y - 1 ) ^{2}}{2 ^{2}} = 1

(h, k) = (2, 1), a = 3, b = 2

Solution steps

\frac{( x - 2 ) ^{2}}{3 ^{2}} + \frac{( y - 1 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 1), a = 3, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (2, 1), a = 3, b = 2

\frac{( x ^{2} )}{9} + \frac{( y ^{2} )}{16} = 1

(\frac{x ^{2}}{64}) + (\frac{y ^{2}}{25}) = 1

1^{2} = (X - 0)^{2} + (Y - 1)^{2}

9 x^{2} + 16 y^{2} - 72 x + 32 y + 16 = 0

x^{2} + 4 y^{2} + 4 x - 8 y = 8

What is ((x-2)^2)/(3^2)+((y-1)^2)/(2^2)=1 ?
The solution to ((x-2)^2)/(3^2)+((y-1)^2)/(2^2)=1 is Ellipse with (h,k)=(2,1),a=3,b=2