What is 1^2=(X-0)^2+(Y-1)^2 ?

The solution to 1^2=(X-0)^2+(Y-1)^2 is Ellipse with (h,k)=(0,1),a=1,b=1

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1^2=(X-0)^2+(Y-1)^2

1^{2} = (X - 0)^{2} + (Y - 1)^{2}

(h, k) = (0, 1), a = 1, b = 1

Solution steps

1^{2} = (X - 0)^{2} + (Y - 1)^{2}

Rewrite

1^{2} - (X - 0)^{2} - (Y - 1)^{2} = 0

in the form of the standard ellipse equation

\frac{( X - 0 ) ^{2}}{1 ^{2}} + \frac{( Y - 1 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 1), a = 1, b = 1

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 1), b = 1, a = 1

9 x^{2} + 16 y^{2} - 72 x + 32 y + 16 = 0

x^{2} + 4 y^{2} + 4 x - 8 y = 8

4 x^{2} + 18 y^{2} = 72

(y - 6)^{2} + 8 (x)^{2} = 64

\frac{( x + 1 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{49} = 1

What is 1^2=(X-0)^2+(Y-1)^2 ?
The solution to 1^2=(X-0)^2+(Y-1)^2 is Ellipse with (h,k)=(0,1),a=1,b=1