What is the center sqrt(13)^2=(x-(-4))^2+(y-(-3))^2 ?

The center sqrt(13)^2=(x-(-4))^2+(y-(-3))^2 is (-4,-3)

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center sqrt(13)^2=(x-(-4))^2+(y-(-3))^2

center

13^{2} = (x - (- 4))^{2} + (y - (- 3))^{2}

(- 4, - 3)

Solution steps

(13)^{2} = (x - (- 4))^{2} + (y - (- 3))^{2}

Rewrite

13^{2} = (x - (- 4))^{2} + (y - (- 3))^{2}

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 3))^{2} = (13)^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 3), r = 13

And the center is:

(- 4, - 3)

(x + 3)^{2} + y^{2} = 25

13.8 + x^{2} + y^{2} = 17

[x + 5]^{2} + [y + 1]^{2} = 9

x^{2} + (y - 1)^{2} = 49

3 x^{2} + 3 y^{2} - 18 x - 18 y + 42 = 0

What is the center sqrt(13)^2=(x-(-4))^2+(y-(-3))^2 ?
The center sqrt(13)^2=(x-(-4))^2+(y-(-3))^2 is (-4,-3)