What is the center (x+3)^2+y^2=25 ?

The center (x+3)^2+y^2=25 is (-3,0)

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center (x+3)^2+y^2=25

center

(x + 3)^{2} + y^{2} = 25

(- 3, 0)

Solution steps

(x + 3)^{2} + y^{2} = 25

Rewrite

(x + 3)^{2} + y^{2} = 25

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 0)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 3, 0), r = 5

And the center is:

(- 3, 0)

13.8 + x^{2} + y^{2} = 17

[x + 5]^{2} + [y + 1]^{2} = 9

x^{2} + (y - 1)^{2} = 49

3 x^{2} + 3 y^{2} - 18 x - 18 y + 42 = 0

(x - 4)^{2} + (y - 1)^{2} = 64