What is (x+1)^2+(y+3)^2=25 ?

The solution to (x+1)^2+(y+3)^2=25 is Circle with (a,b)=(-1,-3),r=5

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(x+1)^2+(y+3)^2=25

(x + 1)^{2} + (y + 3)^{2} = 25

(a, b) = (- 1, - 3), r = 5

Solution steps

(x + 1)^{2} + (y + 3)^{2} = 25

Rewrite

(x + 1)^{2} + (y + 3)^{2} = 25

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 3))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 3), r = 5

(x - 2)^{2} + (y + 5)^{2} = 100

(x + 3.2625400000000 \dots)^{2} + (y + 8)^{2} = + 1936

(\frac{( x - 1 )}{1})^{2} + (\frac{( y - 3 )}{1})^{2} = 1

x^{2} + y^{2} - 22 x + 12 y - 150 = 0

(x + 1)^{2} + (y - 5)^{2} = 9

What is (x+1)^2+(y+3)^2=25 ?
The solution to (x+1)^2+(y+3)^2=25 is Circle with (a,b)=(-1,-3),r=5