What is (x-2)^2+(y+5)^2=100 ?

The solution to (x-2)^2+(y+5)^2=100 is Circle with (a,b)=(2,-5),r=10

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(x-2)^2+(y+5)^2=100

(x - 2)^{2} + (y + 5)^{2} = 100

(a, b) = (2, - 5), r = 10

Solution steps

(x - 2)^{2} + (y + 5)^{2} = 100

Rewrite

(x - 2)^{2} + (y + 5)^{2} = 100

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 5))^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (2, - 5), r = 10

(x + 3.2625400000000 \dots)^{2} + (y + 8)^{2} = + 1936

(\frac{( x - 1 )}{1})^{2} + (\frac{( y - 3 )}{1})^{2} = 1

x^{2} + y^{2} - 22 x + 12 y - 150 = 0

(x + 1)^{2} + (y - 5)^{2} = 9

x^{2} + y^{2} + 20 x - 18 y + 145 = 0

What is (x-2)^2+(y+5)^2=100 ?
The solution to (x-2)^2+(y+5)^2=100 is Circle with (a,b)=(2,-5),r=10