What is 12x^2+12y^2+12x-24y+3=0 ?

The solution to 12x^2+12y^2+12x-24y+3=0 is Circle with (a,b)=(-1/2 ,1),r=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12x^2+12y^2+12x-24y+3=0

12 x^{2} + 12 y^{2} + 12 x - 24 y + 3 = 0

(a, b) = (- \frac{1}{2}, 1), r = 1

Solution steps

12 x^{2} + 12 y^{2} + 12 x - 24 y + 3 = 0

Rewrite

12 x^{2} + 12 y^{2} + 12 x - 24 y + 3 = 0

in the form of the standard circle equation

(x - (- \frac{1}{2}))^{2} + (y - 1)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (- \frac{1}{2}, 1), r = 1

(x + \frac{9}{4})^{2} = \frac{13}{2} - (y - 8)^{2}

x^{2} + y^{2} - 36 x + 12 y + 80 = 0

(x - 4)^{2} + (y + 1)^{2} = 4

(x + 2)^{(2)} + (y + 3)^{(2)} = 7

x^{2} + y^{2} + 8 x - 14 y + 61 = 0

What is 12x^2+12y^2+12x-24y+3=0 ?
The solution to 12x^2+12y^2+12x-24y+3=0 is Circle with (a,b)=(-1/2 ,1),r=1