What is (x+9/4)^2= 13/2-(y-8)^2 ?

The solution to (x+9/4)^2= 13/2-(y-8)^2 is Circle with (a,b)=(-9/4 ,8),r=sqrt(13/2)

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(x+9/4)^2= 13/2-(y-8)^2

(x + \frac{9}{4})^{2} = \frac{13}{2} - (y - 8)^{2}

(a, b) = (- \frac{9}{4}, 8), r = \frac{13}{2}

Solution steps

(x + \frac{9}{4})^{2} = \frac{13}{2} - (y - 8)^{2}

Rewrite

(x + \frac{9}{4})^{2} = \frac{13}{2} - (y - 8)^{2}

in the form of the standard circle equation

(x - (- \frac{9}{4}))^{2} + (y - 8)^{2} = (\frac{13}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{9}{4}, 8), r = \frac{13}{2}

x^{2} + y^{2} - 36 x + 12 y + 80 = 0

(x - 4)^{2} + (y + 1)^{2} = 4

(x + 2)^{(2)} + (y + 3)^{(2)} = 7

x^{2} + y^{2} + 8 x - 14 y + 61 = 0

x^{2} + y^{2} + 6 x - 8 y - 6 = 0

What is (x+9/4)^2= 13/2-(y-8)^2 ?
The solution to (x+9/4)^2= 13/2-(y-8)^2 is Circle with (a,b)=(-9/4 ,8),r=sqrt(13/2)