What is x^2-4y+y^2-21=0 ?

The solution to x^2-4y+y^2-21=0 is Circle with (a,b)=(0,2),r=5

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x^2-4y+y^2-21=0

x^{2} - 4 y + y^{2} - 21 = 0

(a, b) = (0, 2), r = 5

Solution steps

x^{2} - 4 y + y^{2} - 21 = 0

Rewrite

x^{2} - 4 y + y^{2} - 21 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 2)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (0, 2), r = 5

(x - 2)^{(2)} + (y - 3)^{(2)} = 2^{(2)}

6 (x - 3)^{2} + 6 (y + 7)^{2} = 216

(x + \frac{1}{2})^{2} + (y - \frac{4}{5})^{2} = \frac{9}{4}

x^{2} + 8 x + y^{2} - 2 y + 8 = 0

4 x^{2} + 4 y^{2} - 8 y - 21 = 0

What is x^2-4y+y^2-21=0 ?
The solution to x^2-4y+y^2-21=0 is Circle with (a,b)=(0,2),r=5