What is (x-2)^{(2)}+(y-3)^{(2)}=2^{(2)} ?

The solution to (x-2)^{(2)}+(y-3)^{(2)}=2^{(2)} is Circle with (a,b)=(2,3),r=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-2)^{(2)}+(y-3)^{(2)}=2^{(2)}

(x - 2)^{(2)} + (y - 3)^{(2)} = 2^{(2)}

(a, b) = (2, 3), r = 2

Solution steps

(x - 2)^{2} + (y - 3)^{2} = 2^{2}

Rewrite

(x - 2)^{2} + (y - 3)^{2} = 2^{2}

in the form of the standard circle equation

(x - 2)^{2} + (y - 3)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (2, 3), r = 2

6 (x - 3)^{2} + 6 (y + 7)^{2} = 216

(x + \frac{1}{2})^{2} + (y - \frac{4}{5})^{2} = \frac{9}{4}

x^{2} + 8 x + y^{2} - 2 y + 8 = 0

4 x^{2} + 4 y^{2} - 8 y - 21 = 0

x^{(2)} + y^{(2)} - 6 x - 8 y - 3 = 0

What is (x-2)^{(2)}+(y-3)^{(2)}=2^{(2)} ?
The solution to (x-2)^{(2)}+(y-3)^{(2)}=2^{(2)} is Circle with (a,b)=(2,3),r=2