What is (x^2)/5+(y^2)/5 =1 ?

The solution to (x^2)/5+(y^2)/5 =1 is Circle with (a,b)=(0,0),r=sqrt(5)

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(x^2)/5+(y^2)/5 =1

\frac{x ^{2}}{5} + \frac{y ^{2}}{5} = 1

(a, b) = (0, 0), r = 5

Solution steps

\frac{x ^{2}}{5} + \frac{y ^{2}}{5} = 1

Rewrite

\frac{x ^{2}}{5} + \frac{y ^{2}}{5} = 1

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 5

4 x^{2} + 4 y^{2} + 8 y - 45 = 0

x, h (x)^{2} + (8 - x)^{2} = 49

a^{2} + b^{2} = 7^{2}

x^{2} + y^{2} - 18 x + 12 y = - 108

(- 7 - p)^{2} + (0 - q)^{2} = 625

What is (x^2)/5+(y^2)/5 =1 ?
The solution to (x^2)/5+(y^2)/5 =1 is Circle with (a,b)=(0,0),r=sqrt(5)