What is x^2+y^2-18x+12y=-108 ?

The solution to x^2+y^2-18x+12y=-108 is Circle with (a,b)=(9,-6),r=3

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x^2+y^2-18x+12y=-108

x^{2} + y^{2} - 18 x + 12 y = - 108

(a, b) = (9, - 6), r = 3

Solution steps

x^{2} + y^{2} - 18 x + 12 y = - 108

Rewrite

x^{2} + y^{2} - 18 x + 12 y = - 108

in the form of the standard circle equation

(x - 9)^{2} + (y - (- 6))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (9, - 6), r = 3

(- 7 - p)^{2} + (0 - q)^{2} = 625

(2 x)^{2} + (2 y - 1)^{2} = 4^{2}

x^{2} + 20 x + y^{2} + 16 = - 20

x^{2} - 8 x + y^{2} + 4 y - 5 = 0

2 x^{2} + 2 y^{2} - 1 = 0

What is x^2+y^2-18x+12y=-108 ?
The solution to x^2+y^2-18x+12y=-108 is Circle with (a,b)=(9,-6),r=3