What is 74=(24-x)^2+(22-y)^2 ?

The solution to 74=(24-x)^2+(22-y)^2 is Circle with (a,b)=(24,22),r=sqrt(74)

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74=(24-x)^2+(22-y)^2

74 = (24 - x)^{2} + (22 - y)^{2}

(a, b) = (24, 22), r = 74

Solution steps

74 = (24 - x)^{2} + (22 - y)^{2}

Rewrite

74 = (24 - x)^{2} + (22 - y)^{2}

in the form of the standard circle equation

(x - 24)^{2} + (y - 22)^{2} = (74)^{2}

Therefore the circle properties are:

(a, b) = (24, 22), r = 74

(x + 1)^{2} + (y - 1)^{2} = 9 ((x - 2)^{2} + (y + 1)^{2})

x^{2} + y^{2} - 15 = y + 2 x

(x - 4)^{2} + y^{2} \leq 4

x^{2} + y^{2} = 48

(x - 2)^{2} + (y - 2)^{2} = 121

What is 74=(24-x)^2+(22-y)^2 ?
The solution to 74=(24-x)^2+(22-y)^2 is Circle with (a,b)=(24,22),r=sqrt(74)