What is (x+1)^2+(y-1)^2=9((x-2)^2+(y+1)^2) ?

The solution to (x+1)^2+(y-1)^2=9((x-2)^2+(y+1)^2) is Circle with (a,b)=(19/8 ,-5/4),r=(3sqrt(13))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x+1)^2+(y-1)^2=9((x-2)^2+(y+1)^2)

(x + 1)^{2} + (y - 1)^{2} = 9 ((x - 2)^{2} + (y + 1)^{2})

(a, b) = (\frac{19}{8}, - \frac{5}{4}), r = \frac{3 13}{8}

Solution steps

(x + 1)^{2} + (y - 1)^{2} = 9 ((x - 2)^{2} + (y + 1)^{2})

Rewrite

(x + 1)^{2} + (y - 1)^{2} = 9 ((x - 2)^{2} + (y + 1)^{2})

in the form of the standard circle equation

(x - \frac{19}{8})^{2} + (y - (- \frac{5}{4}))^{2} = (\frac{3 13}{8})^{2}

Therefore the circle properties are:

(a, b) = (\frac{19}{8}, - \frac{5}{4}), r = \frac{3 13}{8}

x^{2} + y^{2} - 15 = y + 2 x

(x - 4)^{2} + y^{2} \leq 4

x^{2} + y^{2} = 48

(x - 2)^{2} + (y - 2)^{2} = 121

y^{2} + (x + 3)^{2} = 7

What is (x+1)^2+(y-1)^2=9((x-2)^2+(y+1)^2) ?
The solution to (x+1)^2+(y-1)^2=9((x-2)^2+(y+1)^2) is Circle with (a,b)=(19/8 ,-5/4),r=(3sqrt(13))/8