What is (x+19/2)^2+(y-2sqrt(30))^2=40 ?

The solution to (x+19/2)^2+(y-2sqrt(30))^2=40 is Circle with (a,b)=(-19/2 ,2sqrt(30)),r=sqrt(40)

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(x+19/2)^2+(y-2sqrt(30))^2=40

(x + \frac{19}{2})^{2} + (y - 230)^{2} = 40

(a, b) = (- \frac{19}{2}, 230), r = 40

Solution steps

(x + \frac{19}{2})^{2} + (y - 230)^{2} = 40

Rewrite

(x + \frac{19}{2})^{2} + (y - 230)^{2} = 40

in the form of the standard circle equation

(x - (- \frac{19}{2}))^{2} + (y - 230)^{2} = (40)^{2}

Therefore the circle properties are:

(a, b) = (- \frac{19}{2}, 230), r = 40

x^{2} - 22 x + 49 = - y^{2} + 14 y

x^{2} - 2 x + y^{2} - 4 y = 11

x^{2} + y^{2} - 6 x + 4 y = 0

(y - 1)^{2} + (x - 5)^{2} = 1

x^{(2)} + y^{(2)} - 3 x + 5 y - 14 = 0

What is (x+19/2)^2+(y-2sqrt(30))^2=40 ?
The solution to (x+19/2)^2+(y-2sqrt(30))^2=40 is Circle with (a,b)=(-19/2 ,2sqrt(30)),r=sqrt(40)