What is x^{(2)}+y^{(2)}-3x+5y-14=0 ?

The solution to x^{(2)}+y^{(2)}-3x+5y-14=0 is Circle with (a,b)=(3/2 ,-5/2),r=(3sqrt(5))/(sqrt(2))

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x^{(2)}+y^{(2)}-3x+5y-14=0

x^{(2)} + y^{(2)} - 3 x + 5 y - 14 = 0

(a, b) = (\frac{3}{2}, - \frac{5}{2}), r = \frac{3 5}{2}

Solution steps

x^{2} + y^{2} - 3 x + 5 y - 14 = 0

Rewrite

x^{2} + y^{2} - 3 x + 5 y - 14 = 0

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - (- \frac{5}{2}))^{2} = (\frac{3 5}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, - \frac{5}{2}), r = \frac{3 5}{2}

x^{2} + y^{2} + 10 y + 9 = 0

(x - 15)^{2} + y^{2} = 25

(x + 1)^{2} + (y - 3)^{2} = 49

(x + 1)^{2} + (y - 3)^{2} = 36

x^{2} + y^{2} - 2 y - 9 = 0

What is x^{(2)}+y^{(2)}-3x+5y-14=0 ?
The solution to x^{(2)}+y^{(2)}-3x+5y-14=0 is Circle with (a,b)=(3/2 ,-5/2),r=(3sqrt(5))/(sqrt(2))