What is x^2+(y-5)^2=100 ?

The solution to x^2+(y-5)^2=100 is Circle with (a,b)=(0,5),r=10

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x^2+(y-5)^2=100

x^{2} + (y - 5)^{2} = 100

(a, b) = (0, 5), r = 10

Solution steps

x^{2} + (y - 5)^{2} = 100

Rewrite

x^{2} + (y - 5)^{2} = 100

in the form of the standard circle equation

(x - 0)^{2} + (y - 5)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (0, 5), r = 10

\frac{( x - 1 ) ^{2}}{9} + \frac{( y + 4 ) ^{2}}{9} = 1

x^{2} - 10 x + y^{2} + 7 y + 12 = 0

2 x^{2} + 2 y^{2} + 13 x - 9 y - 20 = 0

5 x^{2} + 5 y^{2} = 245

(x - 0.5)^{2} + (y - 1)^{2} = (\frac{1}{2})^{2}

What is x^2+(y-5)^2=100 ?
The solution to x^2+(y-5)^2=100 is Circle with (a,b)=(0,5),r=10