What is ((x-1)^2)/9+((y+4)^2)/9 =1 ?

The solution to ((x-1)^2)/9+((y+4)^2)/9 =1 is Circle with (a,b)=(1,-4),r=3

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((x-1)^2)/9+((y+4)^2)/9 =1

\frac{( x - 1 ) ^{2}}{9} + \frac{( y + 4 ) ^{2}}{9} = 1

(a, b) = (1, - 4), r = 3

Solution steps

\frac{( x - 1 ) ^{2}}{9} + \frac{( y + 4 ) ^{2}}{9} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{9} + \frac{( y + 4 ) ^{2}}{9} = 1

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 4))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (1, - 4), r = 3

x^{2} - 10 x + y^{2} + 7 y + 12 = 0

2 x^{2} + 2 y^{2} + 13 x - 9 y - 20 = 0

5 x^{2} + 5 y^{2} = 245

(x - 0.5)^{2} + (y - 1)^{2} = (\frac{1}{2})^{2}

x^{2} + y^{2} + 6 x + 14 y + 37 = 0

What is ((x-1)^2)/9+((y+4)^2)/9 =1 ?
The solution to ((x-1)^2)/9+((y+4)^2)/9 =1 is Circle with (a,b)=(1,-4),r=3