What is x^2+y^2-16x+14y+64=0 ?

The solution to x^2+y^2-16x+14y+64=0 is Circle with (a,b)=(8,-7),r=7

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x^2+y^2-16x+14y+64=0

x^{2} + y^{2} - 16 x + 14 y + 64 = 0

(a, b) = (8, - 7), r = 7

Solution steps

x^{2} + y^{2} - 16 x + 14 y + 64 = 0

Rewrite

x^{2} + y^{2} - 16 x + 14 y + 64 = 0

in the form of the standard circle equation

(x - 8)^{2} + (y - (- 7))^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (8, - 7), r = 7

x^{2} + y^{2} + \frac{3}{5} x - \frac{7}{6} y - \frac{1}{5} = 0

(x + 4)^{2} + (y - 6)^{2} = 25

x^{2} + (y + 2)^{2} = 9

x^{2} + (y + 2)^{2} = 5

(x - \frac{23}{5})^{2} + (y + \frac{2}{5})^{2} = \frac{373}{5}

What is x^2+y^2-16x+14y+64=0 ?
The solution to x^2+y^2-16x+14y+64=0 is Circle with (a,b)=(8,-7),r=7