What is x^2+y^2+3/5 x-7/6 y-1/5 =0 ?

The solution to x^2+y^2+3/5 x-7/6 y-1/5 =0 is Circle with (a,b)=(-3/10 , 7/12),r=(sqrt(2269))/(60)

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x^2+y^2+3/5 x-7/6 y-1/5 =0

x^{2} + y^{2} + \frac{3}{5} x - \frac{7}{6} y - \frac{1}{5} = 0

(a, b) = (- \frac{3}{10}, \frac{7}{12}), r = \frac{2269}{60}

Solution steps

x^{2} + y^{2} + \frac{3}{5} x - \frac{7}{6} y - \frac{1}{5} = 0

Rewrite

x^{2} + y^{2} + \frac{3}{5} x - \frac{7}{6} y - \frac{1}{5} = 0

in the form of the standard circle equation

(x - (- \frac{3}{10}))^{2} + (y - \frac{7}{12})^{2} = (\frac{2269}{60})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{3}{10}, \frac{7}{12}), r = \frac{2269}{60}

(x + 4)^{2} + (y - 6)^{2} = 25

x^{2} + (y + 2)^{2} = 9

x^{2} + (y + 2)^{2} = 5

(x - \frac{23}{5})^{2} + (y + \frac{2}{5})^{2} = \frac{373}{5}

x^{2} + (y + 2)^{2} = 1

What is x^2+y^2+3/5 x-7/6 y-1/5 =0 ?
The solution to x^2+y^2+3/5 x-7/6 y-1/5 =0 is Circle with (a,b)=(-3/10 , 7/12),r=(sqrt(2269))/(60)