What is (x-5)^2+(y-6)^2=20 ?

The solution to (x-5)^2+(y-6)^2=20 is Circle with (a,b)=(5,6),r=sqrt(20)

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(x-5)^2+(y-6)^2=20

(x - 5)^{2} + (y - 6)^{2} = 20

(a, b) = (5, 6), r = 20

Solution steps

(x - 5)^{2} + (y - 6)^{2} = 20

Rewrite

(x - 5)^{2} + (y - 6)^{2} = 20

in the form of the standard circle equation

(x - 5)^{2} + (y - 6)^{2} = (20)^{2}

Therefore the circle properties are:

(a, b) = (5, 6), r = 20

x^{2} - 6 x + y^{2} + 10 y + 9 = 0

x^{2} + y^{2} + 12 x - 8 y + 16 = 0

(x - 4)^{2} + (y - 20)^{2} = 592^{2}

x^{2} + x + y^{2} + \frac{8}{3} y - \frac{1223}{36} = 0

(x - 4)^{2} + (y - 2)^{2} = 36

What is (x-5)^2+(y-6)^2=20 ?
The solution to (x-5)^2+(y-6)^2=20 is Circle with (a,b)=(5,6),r=sqrt(20)