What is x^2+y^2+12x-8y+16=0 ?

The solution to x^2+y^2+12x-8y+16=0 is Circle with (a,b)=(-6,4),r=6

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x^2+y^2+12x-8y+16=0

x^{2} + y^{2} + 12 x - 8 y + 16 = 0

(a, b) = (- 6, 4), r = 6

Solution steps

x^{2} + y^{2} + 12 x - 8 y + 16 = 0

Rewrite

x^{2} + y^{2} + 12 x - 8 y + 16 = 0

in the form of the standard circle equation

(x - (- 6))^{2} + (y - 4)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 6, 4), r = 6

(x - 4)^{2} + (y - 20)^{2} = 592^{2}

x^{2} + x + y^{2} + \frac{8}{3} y - \frac{1223}{36} = 0

(x - 4)^{2} + (y - 2)^{2} = 36

x^{2} + y^{2} + 2 x - 10 y + 1 = 0

(x - 2)^{2} + (y + 8)^{2} = 144

What is x^2+y^2+12x-8y+16=0 ?
The solution to x^2+y^2+12x-8y+16=0 is Circle with (a,b)=(-6,4),r=6