What is x^2+8x+y^2-9y=6 ?

The solution to x^2+8x+y^2-9y=6 is Circle with (a,b)=(-4, 9/2),r= 13/2

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x^2+8x+y^2-9y=6

x^{2} + 8 x + y^{2} - 9 y = 6

(a, b) = (- 4, \frac{9}{2}), r = \frac{13}{2}

Solution steps

x^{2} + 8 x + y^{2} - 9 y = 6

Rewrite

x^{2} + 8 x + y^{2} - 9 y = 6

in the form of the standard circle equation

(x - (- 4))^{2} + (y - \frac{9}{2})^{2} = (\frac{13}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 4, \frac{9}{2}), r = \frac{13}{2}

x^{2} + y^{2} + 2 x - 8 y - 8 = 0

(x - 4)^{(2)} + (y - 7)^{(2)} = 4

4 x^{2} - 8 \geq - 4 y^{2}

x^{2} + y^{2} - 4 x + 2 = 0

(a + b) 2 = a^{2} + b^{2}

What is x^2+8x+y^2-9y=6 ?
The solution to x^2+8x+y^2-9y=6 is Circle with (a,b)=(-4, 9/2),r= 13/2