What is (a+b)2=a^2+b^2 ?

The solution to (a+b)2=a^2+b^2 is Circle with (a,b)=(1,1),r=sqrt(2)

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(a+b)2=a^2+b^2

(a + b) 2 = a^{2} + b^{2}

(a, b) = (1, 1), r = 2

Solution steps

(a + b) \cdot 2 = a^{2} + b^{2}

Rewrite

(a + b) 2 = a^{2} + b^{2}

in the form of the standard circle equation

(a - 1)^{2} + (b - 1)^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (1, 1), r = 2

x^{2} - 10 x + 25 + y^{2} - 8 y + 16 = 64

(x - 2)^{2} + (y - 4)^{2} = 25

(x - 2)^{2} + (y - 4)^{2} = 16

(x + 4)^{2} + (y + 1)^{2} = 25

x^{2} + y^{2} - 8 x + 14 y + 40 = 0

What is (a+b)2=a^2+b^2 ?
The solution to (a+b)2=a^2+b^2 is Circle with (a,b)=(1,1),r=sqrt(2)