What is x^2+(y-8)^2=5 ?

The solution to x^2+(y-8)^2=5 is Circle with (a,b)=(0,8),r=sqrt(5)

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x^2+(y-8)^2=5

x^{2} + (y - 8)^{2} = 5

(a, b) = (0, 8), r = 5

Solution steps

x^{2} + (y - 8)^{2} = 5

Rewrite

x^{2} + (y - 8)^{2} = 5

in the form of the standard circle equation

(x - 0)^{2} + (y - 8)^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (0, 8), r = 5

(x - 6)^{2} + (y - 4)^{2} = 5^{2}

25.314 4^{2} = (27.2 - x)^{2} + (27.2 - y)^{2}

x^{2} - 4 x + y^{2} + 6 y + 4 = 0

(x + 1)^{2} + (y - 4)^{2} = 9

(x - 3)^{2} + (y - 2)^{2} = 3^{2}

What is x^2+(y-8)^2=5 ?
The solution to x^2+(y-8)^2=5 is Circle with (a,b)=(0,8),r=sqrt(5)