What is (x-6)^2+(y-4)^2=5^2 ?

The solution to (x-6)^2+(y-4)^2=5^2 is Circle with (a,b)=(6,4),r=5

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(x-6)^2+(y-4)^2=5^2

(x - 6)^{2} + (y - 4)^{2} = 5^{2}

(a, b) = (6, 4), r = 5

Solution steps

(x - 6)^{2} + (y - 4)^{2} = 5^{2}

Rewrite

(x - 6)^{2} + (y - 4)^{2} = 5^{2}

in the form of the standard circle equation

(x - 6)^{2} + (y - 4)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (6, 4), r = 5

25.314 4^{2} = (27.2 - x)^{2} + (27.2 - y)^{2}

x^{2} - 4 x + y^{2} + 6 y + 4 = 0

(x + 1)^{2} + (y - 4)^{2} = 9

(x - 3)^{2} + (y - 2)^{2} = 3^{2}

(x - 0)^{2} + (y - 0)^{2} = 4^{2}

What is (x-6)^2+(y-4)^2=5^2 ?
The solution to (x-6)^2+(y-4)^2=5^2 is Circle with (a,b)=(6,4),r=5