What is x^2+y^2+10x-16y-55=0 ?

The solution to x^2+y^2+10x-16y-55=0 is Circle with (a,b)=(-5,8),r=12

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x^2+y^2+10x-16y-55=0

x^{2} + y^{2} + 10 x - 16 y - 55 = 0

(a, b) = (- 5, 8), r = 12

Solution steps

x^{2} + y^{2} + 10 x - 16 y - 55 = 0

Rewrite

x^{2} + y^{2} + 10 x - 16 y - 55 = 0

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 8)^{2} = 1 2^{2}

Therefore the circle properties are:

(a, b) = (- 5, 8), r = 12

(x + 8)^{2} + (y + 5)^{2} = 256

x^{2} - 16 x + y^{2} - 36 = 0

(x - \frac{7}{4})^{2} + (y - \frac{3}{4})^{2} = \frac{169}{16}

x^{2} + y^{2} + 6 x - 22 y + 120 = 0

(x + 4)^{2} + (y + 5)^{2} = 36

What is x^2+y^2+10x-16y-55=0 ?
The solution to x^2+y^2+10x-16y-55=0 is Circle with (a,b)=(-5,8),r=12