What is x^2-16x+y^2-36=0 ?

The solution to x^2-16x+y^2-36=0 is Circle with (a,b)=(8,0),r=10

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x^2-16x+y^2-36=0

x^{2} - 16 x + y^{2} - 36 = 0

(a, b) = (8, 0), r = 10

Solution steps

x^{2} - 16 x + y^{2} - 36 = 0

Rewrite

x^{2} - 16 x + y^{2} - 36 = 0

in the form of the standard circle equation

(x - 8)^{2} + (y - 0)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (8, 0), r = 10

(x - \frac{7}{4})^{2} + (y - \frac{3}{4})^{2} = \frac{169}{16}

x^{2} + y^{2} + 6 x - 22 y + 120 = 0

(x + 4)^{2} + (y + 5)^{2} = 36

(x - 6)^{2} + (y - 7)^{2} = 8^{2}

(x - 3)^{2} + (y - 2)^{2} = 5

What is x^2-16x+y^2-36=0 ?
The solution to x^2-16x+y^2-36=0 is Circle with (a,b)=(8,0),r=10